如何解决Django: TypeError at /login/ __init__() 需要 1 个位置参数，但给出了 2 个？

我试图在我的简单项目中将 Django 版本从 1.9 更新到 3.2.5，一切看起来都不错。但是当我尝试访问登录页面时，在浏览器中出现以下错误：

Request Method:     GET
Request URL:    http://localhost:49801/login/
Django Version:     3.2.5
Exception Type:     TypeError
Exception Value:    __init__() takes 1 positional argument but 2 were given

Exception Location:     C:\Program Files (x86)\Microsoft Visual Studio\Shared\python37_64\lib\site-packages\django\core\handlers\base.py,line 181,in _get_response
Python Executable:  C:\Program Files (x86)\Microsoft Visual Studio\Shared\python37_64\python.exe
Python Version:     3.7.8
Python Path:    

[''C:\\source\\repos\\aud'',''C:\\Program Files (x86)\\Microsoft Visual Studio\\Shared\\python37_64\\python37.zip'',''C:\\Program Files (x86)\\Microsoft Visual Studio\\Shared\\python37_64\\DLLs'',''C:\\Program Files (x86)\\Microsoft Visual Studio\\Shared\\python37_64\\lib'',''C:\\Program Files (x86)\\Microsoft Visual Studio\\Shared\\python37_64'',''C:\\Program Files (x86)\\Microsoft Visual Studio\\Shared\\python37_64\\lib\\site-packages'']

追溯：

Environment:
Request Method: GET
Request URL: http://localhost:49801/login/
Django Version: 3.2.5
Python Version: 3.7.8
Installed Applications:
[''app'',''django.contrib.admin'',''django.contrib.auth'',''django.contrib.contenttypes'',''django.contrib.sessions'',''django.contrib.messages'',''django.contrib.staticfiles'']
Installed Middleware:
[''django.middleware.security.SecurityMiddleware'',''django.contrib.sessions.middleware.SessionMiddleware'',''django.middleware.common.CommonMiddleware'',''django.middleware.csrf.CsrfViewMiddleware'',''django.contrib.auth.middleware.AuthenticationMiddleware'',''django.contrib.messages.middleware.MessageMiddleware'',''django.middleware.clickjacking.XFrameOptionsMiddleware'']

Traceback (most recent call last):
  File "C:\Program Files (x86)\Microsoft Visual Studio\Shared\python37_64\lib\site-packages\django\core\handlers\exception.py",line 47,in inner
    response = get_response(request)
  File "C:\Program Files (x86)\Microsoft Visual Studio\Shared\python37_64\lib\site-packages\django\core\handlers\base.py",in _get_response
    response = wrapped_callback(request,*callback_args,**callback_kwargs)

Exception Type: TypeError at /login/
Exception Value: __init__() takes 1 positional argument but 2 were given

来自 settings.py 的其他信息：

TEMPLATES = [
    {
        ''BACKEND'': ''django.template.backends.django.DjangoTemplates'',''Dirs'': [],''APP_Dirs'': True,''OPTIONS'': {
            ''context_processors'': [
                ''django.template.context_processors.debug'',''django.template.context_processors.request'',''django.contrib.auth.context_processors.auth'',''django.contrib.messages.context_processors.messages'',''django.template.context_processors.media'',''app.context_processors.cart'',],},]

forms.py:

from django import forms
from django.contrib.auth.forms import AuthenticationForm
from django.utils.translation import ugettext_lazy as _
from django.db import models
from.models import Comment,Blog,OptionsModel,Order

class BootstrapAuthenticationForm(AuthenticationForm):
    """Authentication form which uses boostrap CSS."""
    username = forms.CharField(max_length=254,widget=forms.TextInput({
                                   ''class'': ''form-control'',''placeholder'': ''Имя пользователя''}))
    password = forms.CharField(label=_("Password"),widget=forms.PasswordInput({
                                   ''class'': ''form-control'',''placeholder'':''Пароль пользователя''}))

urls.py:

from datetime import datetime
from django.conf.urls import url,include
import django.contrib.auth.views

import app.forms,app.views

# Uncomment the next lines to enable the admin:
from django.contrib import admin
admin.autodiscover()

from django.conf.urls.static import static 
from django.contrib.staticfiles.urls import staticfiles_urlpatterns 
from django.conf import settings
from django.views.generic import RedirectView

urlpatterns = [
    url(r''^about$'',app.views.about,name=''about''),url(r''^links$'',app.views.links,name=''links''),url(r''^registration$'',app.views.registration,name=''registration''),url(r''^login/$'',django.contrib.auth.views.LoginView,{
            ''template_name'': ''app/login.html'',''authentication_form'': app.forms.BootstrapAuthenticationForm,''extra_context'':
            {
                ''title'': ''Вход пользователя'',''year'': datetime.Now().year,}
        },name=''login''),url(r''^logout$'',django.contrib.auth.views.logoutView,{
            ''next_page'': ''/'',name=''logout''),]

views.py：

from django.shortcuts import render,redirect,get_object_or_404
from django.views.decorators.http import require_POST
from django.contrib.admin.views.decorators import staff_member_required
from django.http import HttpRequest
from django.template import RequestContext
from datetime import datetime
from django.contrib.auth.models import User
from django.contrib.auth.forms import UserCreationForm
from django.db import models 

登录.html：

{% extends "app/layout.html" %}
<!--♕-->
{% block content %}

<h2>{{ title }}</h2>
<div>
    <div>
        <section id="loginForm">
            <form action="." method="post">
                {% csrf_token %}
                <h4>Используйте аккаунт для входа.</h4>
                <hr />
                <div>
                    <label for="id_username">Имя пользователя</label>
                    <div>
                        {{ form.username }}
                    </div>
                </div>
                <div>
                    <label for="id_password">Пароль</label>
                    <div>
                        {{ form.password }}
                    </div>
                </div>
                <div>
                    <div>
                        <input type="hidden" name="next" value="/" />
                        <input type="submit" value="Войти"/>
                    </div>
                </div>

                {% if form.errors %}
                    <p>Введите правильное имя пользователя и/или пароль.</p>
                {% endif %}

            </form>
        </section>
    </div>
    <div>
        <section id="socialLoginForm"></section>
    </div>
</div>

{% endblock %}


{% block scripts %}

{% load static %}

<script src="{% static ''app/scripts/jquery.validate.min.js'' %}"></script>

{% endblock %}

还更新了许多脚本：bootstrap.js 和 .css 从 3 到 v5.0.2； jquery 从 1.10.2 到 3.6.0； jquery.validate.js 和 respond.js 到最新版本。

如果有人对我收到此错误的原因有任何见解，我将不胜感激。

更新了 url.py 但有同样的错误（感谢 Willem Van Onsem）：

from django.conf.urls import include,re_path

re_path(r''^login/$'',django.contrib.auth.views.LoginView.as_view(
    {
        ''template_name'': ''app/login.html'',''extra_context'':
        {
            ''title'': ''Вход пользователя'',}
    }),re_path(r''^logout$'',django.contrib.auth.views.logoutView.as_view(
    {
        ''next_page'': ''/'',}),

仅在 urls.py 中使用此代码，错误消失了，但出现了新的错误：

re_path(r''^login/$'',django.contrib.auth.views.LoginView.as_view(),django.contrib.auth.views.logoutView.as_view(),

错误（因为我无法传输 as_view({''template_name'': ''app/login.html''}) ）：

TemplateDoesNotExist at /login/
registration/login.html
Request Method:     GET
Request URL:    http://localhost:62067/login/
Django Version:     3.2.5
Exception Type:     TemplateDoesNotExist
Exception Value:    registration/login.html

解决方法

url(
    r''^login/$'',django.contrib.auth.views.LoginView.as_view(
        template_name=''app/login.html'',authentication_form=app.forms.BootstrapAuthenticationForm,extra_context{ ''title'': ''Вход пользователя'',''year'': datetime.now().year }
    )
    name=''login''
),url(
    r''^logout$'',django.contrib.auth.views.LogoutView.as_view(next_page=''/'')
    name=''logout''
)

    def direccion_func(coordenadas):
           dir = geolocator.reverse(coordenadas)
           return dir.address
    
        direccion = pandas_udf(direccion_func,returnType = StringType())
    
       paradasRuta1DF = 

paradasRuta1DF.withColumn('Direccion',direccion_func(F.col("LatLong")))