在本文中,我们将带你了解能够使用SQL查询来计算表中两个不同行之间的时间差在这篇文章中,同时我们还将给您一些技巧,以帮助您实现更有效的golang计算两个时间的时间差、go语言计算两个时间的时间差方法
在本文中,我们将带你了解能够使用SQL查询来计算表中两个不同行之间的时间差在这篇文章中,同时我们还将给您一些技巧,以帮助您实现更有效的golang 计算两个时间的时间差、go语言计算两个时间的时间差方法、Java中两个日期之间的时间差、mysql – 如何在Sql中两个现有行之间的表中插入行。
本文目录一览:- 能够使用SQL查询来计算表中两个不同行之间的时间差
- golang 计算两个时间的时间差
- go语言计算两个时间的时间差方法
- Java中两个日期之间的时间差
- mysql – 如何在Sql中两个现有行之间的表中插入行
能够使用SQL查询来计算表中两个不同行之间的时间差
对于MYSQL Server版本8 +
如果您正在使用MySQL Server的最新版本(例如8.0版),则可以尝试使用 LAG()函数。
样品表:
CREATE TABLE WorkLog (
employee_name varchar(10),Shipping_Time DATETIME,PRIMARY KEY (employee_name,Shipping_Time)
);
样本数据:
INSERT INTO WorkLog(employee_name,Shipping_Time) VALUES("Joe","2020-10-02 12:00:00.000");
INSERT INTO WorkLog(employee_name,"2020-10-02 12:01:30.000");
INSERT INTO WorkLog(employee_name,"2020-10-02 12:05:30.000");
INSERT INTO WorkLog(employee_name,"2020-10-02 12:10:00.000");
INSERT INTO WorkLog(employee_name,"2020-10-02 12:20:00.000");
INSERT INTO WorkLog(employee_name,Shipping_Time) VALUES("Sue","2020-10-02 12:20:00.000");
SQL查询-以秒为单位获取结果:
SELECT employee_name,Shipping_Time,TIMESTAMPDIFF(SECOND,(LAG(Shipping_Time,1) OVER (PARTITION BY employee_name)),Shipping_Time) AS TimeDiffInSeconds
FROM WorkLog
ORDER BY employee_name,Shipping_Time;
输出:
| employee_name | Shipping_Time | TimeDiffInSeconds |
| ------------- | ------------------- | ----------------- |
| Joe | 2020-10-02 12:00:00 | |
| Joe | 2020-10-02 12:01:30 | 90 |
| Joe | 2020-10-02 12:05:30 | 240 |
| Joe | 2020-10-02 12:10:00 | 270 |
| Joe | 2020-10-02 12:20:00 | 600 |
| Sue | 2020-10-02 12:00:00 | |
| Sue | 2020-10-02 12:01:30 | 90 |
| Sue | 2020-10-02 12:05:30 | 240 |
| Sue | 2020-10-02 12:10:00 | 270 |
| Sue | 2020-10-02 12:20:00 | 600 |
SQL查询-以时间(hh:mm:ss)的形式获取结果:
SELECT employee_name,SEC_TO_TIME(TIMESTAMPDIFF(SECOND,Shipping_Time)) AS "TimeDiff hh:mm:ss"
FROM WorkLog
ORDER BY employee_name,Shipping_Time;
输出:
| employee_name | Shipping_Time | TimeDiff hh:mm:ss |
| ------------- | ------------------- | ----------------- |
| Joe | 2020-10-02 12:00:00 | |
| Joe | 2020-10-02 12:01:30 | 00:01:30 |
| Joe | 2020-10-02 12:05:30 | 00:04:00 |
| Joe | 2020-10-02 12:10:00 | 00:04:30 |
| Joe | 2020-10-02 12:20:00 | 00:10:00 |
| Sue | 2020-10-02 12:00:00 | |
| Sue | 2020-10-02 12:01:30 | 00:01:30 |
| Sue | 2020-10-02 12:05:30 | 00:04:00 |
| Sue | 2020-10-02 12:10:00 | 00:04:30 |
| Sue | 2020-10-02 12:20:00 | 00:10:00 |
参考:https://dev.mysql.com/doc/refman/8.0/en/window-function-descriptions.html#function_lag
对于MS SQL Server
使用OP评论中的新信息:
样品表:
CREATE TABLE JSSHIPMENTTABLE (
CREATEDBY varchar(10),CREATEDDATETIME DATETIME,PRIMARY KEY (CREATEDBY,CREATEDDATETIME)
);
样本数据:
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,CREATEDDATETIME) VALUES('Joe','2020-10-02 12:00:00.000');
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,'2020-10-02 12:01:30.000');
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,CREATEDDATETIME) VALUES('Sue',CREATEDDATETIME) VALUES('Sam Colton','2020-10-01 12:00:00.000');
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,'2020-10-01 12:01:30.000');
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,'2020-10-01 12:05:30.000');
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,'2020-10-01 12:10:00.000');
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,'2020-10-01 12:20:00.000');
MS SQL Server查询-以秒为单位获取结果:
SELECT CREATEDBY,CREATEDDATETIME,datediff(second,(lag(CREATEDDATETIME,1) over (PARTITION by CREATEDBY ORDER BY CREATEDDATETIME)),CREATEDDATETIME) as TimeDiffinSeconds
from JSSHIPMENTTABLE
where convert(date,23) = '2020-10-01' and CREATEDBY like '%Colton%' order by CREATEDBY,CREATEDDATETIME
输出:
CREATEDBY CREATEDDATETIME TimeDiffinSeconds
----------------------------------------------------------
Sam Colton 2020-10-01 12:00:00.000 NULL
Sam Colton 2020-10-01 12:01:30.000 90
Sam Colton 2020-10-01 12:05:30.000 240
Sam Colton 2020-10-01 12:10:00.000 270
Sam Colton 2020-10-01 12:20:00.000 600
,
尝试此查询。您可以编辑DATEDIFF函数,以分钟,小时,天或任何所需的增量为您提供差异。
SELECT a.user,a.[date/time],DATEDIFF(second,b.[date/time],a.[date/time]) AS [time difference]
FROM #YourTable a
OUTER APPLY (
SELECT TOP 1 *
FROM #YourTable b
WHERE a.user = b.user
AND b.[date/time] < a.[date/time]
ORDER BY [date/time] DESC
) b
ORDER BY a.user,a.[date/time] ASC
,
-- Sample Table:
CREATE TABLE WorkLog (
employee_name varchar(10),Shipping_Time)
);
-- Sample Data:
INSERT INTO WorkLog(employee_name,Shipping_Time) VALUES('Joe','2020-10-02 12:00:00.000');
INSERT INTO WorkLog(employee_name,'2020-10-02 12:01:30.000');
INSERT INTO WorkLog(employee_name,'2020-10-02 12:05:30.000');
INSERT INTO WorkLog(employee_name,'2020-10-02 12:10:00.000');
INSERT INTO WorkLog(employee_name,'2020-10-02 12:20:00.000');
Select *,FORMAT(Shipping_Time - LAG(Shipping_Time) OVER (ORDER BY employee_name),'mm:ss') As timeDiference
From WorkLog
Order By Shipping_Time ASC
-- Results:
employee_name Shipping_Time timeDiference
Joe 2020-10-02 12:00:00.000 NULL
Joe 2020-10-02 12:01:30.000 01:30
Joe 2020-10-02 12:05:30.000 04:00
Joe 2020-10-02 12:10:00.000 04:30
Joe 2020-10-02 12:20:00.000 10:00
golang 计算两个时间的时间差
package main import ( "fmt" "time" ) func main() { //Add方法和Sub方法是相反的,获取t0和t1的时间距离d是使用Sub,将t0加d获取t1就是使用Add方法 k := time.Now() //一天之前 d,_ := time.ParseDuration("-24h") fmt.Println(k.Add(d)) //一周之前 fmt.Println(k.Add(d * 7)) //一月之前 fmt.Println(k.Add(d * 30)) }
go语言计算两个时间的时间差方法
本文实例讲述了go语言计算两个时间的时间差方法。分享给大家供大家参考。具体分析如下:
go语言计算两个时间的时间差,代码很简单,返回1天前、1周前还是1月前的时间
- package mainimport ( "fmt" "time")func main() {//Add方法和Sub方法是相反的,获取t0和t1的时间距离d是使用Sub//将t0加d获取t1就是使用Add方法 k := time.Now() //一天之前 d, _ := time.ParseDuration("-24h") fmt.Println(k.Add(d)) //一周之前 fmt.Println(k.Add(d * 7)) //一月之前 fmt.Println(k.Add(d * 30))}
希望本文所述对大家的Python程序设计有所帮助。
Java中两个日期之间的时间差
我必须找到java中两个不同日期对象之间的时间差异,如果该时间超过5秒,我必须使会话无效。
这是场景:
我有一个jsp页面,它每5秒设置一次会话
session.setAttribute( "sessionAccessedAt",new Date() );
我还有另一个jsp页面,每1秒访问一次,
Date date2 = new Date();
现在,我必须在我提到的另一个jsp中进行比较,并使会话无效,
Date date1 = (Date)session.getAttribute("sessionAccessedAt");
Date date2 = new Date();
Differnce = date2 - date1;
因此,如果差异超过5秒,则会话无效。
mysql – 如何在Sql中两个现有行之间的表中插入行
我有一个包含9条记录的表,但我想在第5和第6条记录之间插入一行.
UPDATE mytable SET id = id + 1 where id > 5 ORDER BY id ASC
insert into mytable (id,..) values (6,...)
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