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能够使用SQL查询来计算表中两个不同行之间的时间差

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在本文中,我们将带你了解能够使用SQL查询来计算表中两个不同行之间的时间差在这篇文章中,同时我们还将给您一些技巧,以帮助您实现更有效的golang计算两个时间的时间差、go语言计算两个时间的时间差方法

在本文中,我们将带你了解能够使用SQL查询来计算表中两个不同行之间的时间差在这篇文章中,同时我们还将给您一些技巧,以帮助您实现更有效的golang 计算两个时间的时间差、go语言计算两个时间的时间差方法、Java中两个日期之间的时间差、mysql – 如何在Sql中两个现有行之间的表中插入行

本文目录一览:

能够使用SQL查询来计算表中两个不同行之间的时间差

能够使用SQL查询来计算表中两个不同行之间的时间差

对于MYSQL Server版本8 +

如果您正在使用MySQL Server的最新版本(例如8.0版),则可以尝试使用 LAG()函数

样品表:

CREATE TABLE WorkLog (
    employee_name varchar(10),Shipping_Time DATETIME,PRIMARY KEY (employee_name,Shipping_Time)
);

样本数据:

INSERT INTO WorkLog(employee_name,Shipping_Time) VALUES("Joe","2020-10-02 12:00:00.000");
INSERT INTO WorkLog(employee_name,"2020-10-02 12:01:30.000");
INSERT INTO WorkLog(employee_name,"2020-10-02 12:05:30.000");
INSERT INTO WorkLog(employee_name,"2020-10-02 12:10:00.000");
INSERT INTO WorkLog(employee_name,"2020-10-02 12:20:00.000");

INSERT INTO WorkLog(employee_name,Shipping_Time) VALUES("Sue","2020-10-02 12:20:00.000");

SQL查询-以秒为单位获取结果:

SELECT employee_name,Shipping_Time,TIMESTAMPDIFF(SECOND,(LAG(Shipping_Time,1) OVER (PARTITION BY employee_name)),Shipping_Time) AS TimeDiffInSeconds
FROM WorkLog
ORDER BY employee_name,Shipping_Time; 

输出:

| employee_name | Shipping_Time       | TimeDiffInSeconds |
| ------------- | ------------------- | ----------------- |
| Joe           | 2020-10-02 12:00:00 |                   |
| Joe           | 2020-10-02 12:01:30 | 90                |
| Joe           | 2020-10-02 12:05:30 | 240               |
| Joe           | 2020-10-02 12:10:00 | 270               |
| Joe           | 2020-10-02 12:20:00 | 600               |
| Sue           | 2020-10-02 12:00:00 |                   |
| Sue           | 2020-10-02 12:01:30 | 90                |
| Sue           | 2020-10-02 12:05:30 | 240               |
| Sue           | 2020-10-02 12:10:00 | 270               |
| Sue           | 2020-10-02 12:20:00 | 600               |

SQL查询-以时间(hh:mm:ss)的形式获取结果:

SELECT employee_name,SEC_TO_TIME(TIMESTAMPDIFF(SECOND,Shipping_Time)) AS "TimeDiff hh:mm:ss"
FROM WorkLog
ORDER BY employee_name,Shipping_Time;

输出:

| employee_name | Shipping_Time       | TimeDiff hh:mm:ss |
| ------------- | ------------------- | ----------------- |
| Joe           | 2020-10-02 12:00:00 |                   |
| Joe           | 2020-10-02 12:01:30 | 00:01:30          |
| Joe           | 2020-10-02 12:05:30 | 00:04:00          |
| Joe           | 2020-10-02 12:10:00 | 00:04:30          |
| Joe           | 2020-10-02 12:20:00 | 00:10:00          |
| Sue           | 2020-10-02 12:00:00 |                   |
| Sue           | 2020-10-02 12:01:30 | 00:01:30          |
| Sue           | 2020-10-02 12:05:30 | 00:04:00          |
| Sue           | 2020-10-02 12:10:00 | 00:04:30          |
| Sue           | 2020-10-02 12:20:00 | 00:10:00          |

参考:https://dev.mysql.com/doc/refman/8.0/en/window-function-descriptions.html#function_lag


对于MS SQL Server

使用OP评论中的新信息:

样品表:

CREATE TABLE JSSHIPMENTTABLE (
    CREATEDBY varchar(10),CREATEDDATETIME DATETIME,PRIMARY KEY (CREATEDBY,CREATEDDATETIME)
);

样本数据:

INSERT INTO JSSHIPMENTTABLE(CREATEDBY,CREATEDDATETIME) VALUES('Joe','2020-10-02 12:00:00.000');
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,'2020-10-02 12:01:30.000');

INSERT INTO JSSHIPMENTTABLE(CREATEDBY,CREATEDDATETIME) VALUES('Sue',CREATEDDATETIME) VALUES('Sam Colton','2020-10-01 12:00:00.000');
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,'2020-10-01 12:01:30.000');
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,'2020-10-01 12:05:30.000');
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,'2020-10-01 12:10:00.000');
INSERT INTO JSSHIPMENTTABLE(CREATEDBY,'2020-10-01 12:20:00.000');

MS SQL Server查询-以秒为单位获取结果:

SELECT CREATEDBY,CREATEDDATETIME,datediff(second,(lag(CREATEDDATETIME,1) over (PARTITION by CREATEDBY ORDER BY CREATEDDATETIME)),CREATEDDATETIME) as TimeDiffinSeconds
from JSSHIPMENTTABLE
where convert(date,23) = '2020-10-01' and CREATEDBY like '%Colton%' order by CREATEDBY,CREATEDDATETIME

输出:

CREATEDBY   CREATEDDATETIME              TimeDiffinSeconds
----------------------------------------------------------
Sam Colton  2020-10-01 12:00:00.000      NULL
Sam Colton  2020-10-01 12:01:30.000      90
Sam Colton  2020-10-01 12:05:30.000      240
Sam Colton  2020-10-01 12:10:00.000      270
Sam Colton  2020-10-01 12:20:00.000      600
,

尝试此查询。您可以编辑DATEDIFF函数,以分钟,小时,天或任何所需的增量为您提供差异。

SELECT a.user,a.[date/time],DATEDIFF(second,b.[date/time],a.[date/time]) AS [time difference]
FROM #YourTable a
OUTER APPLY (
    SELECT TOP 1 *
    FROM #YourTable b
    WHERE a.user = b.user
    AND b.[date/time] < a.[date/time]
    ORDER BY [date/time] DESC
) b
ORDER BY a.user,a.[date/time] ASC
,
-- Sample Table:
CREATE TABLE WorkLog (
    employee_name varchar(10),Shipping_Time)
);

-- Sample Data:
INSERT INTO WorkLog(employee_name,Shipping_Time) VALUES('Joe','2020-10-02 12:00:00.000');
INSERT INTO WorkLog(employee_name,'2020-10-02 12:01:30.000');
INSERT INTO WorkLog(employee_name,'2020-10-02 12:05:30.000');
INSERT INTO WorkLog(employee_name,'2020-10-02 12:10:00.000');
INSERT INTO WorkLog(employee_name,'2020-10-02 12:20:00.000');

Select *,FORMAT(Shipping_Time - LAG(Shipping_Time) OVER (ORDER BY employee_name),'mm:ss') As timeDiference
From WorkLog
Order By Shipping_Time ASC

-- Results:
employee_name   Shipping_Time   timeDiference
Joe 2020-10-02  12:00:00.000    NULL
Joe 2020-10-02  12:01:30.000    01:30
Joe 2020-10-02  12:05:30.000    04:00
Joe 2020-10-02  12:10:00.000    04:30
Joe 2020-10-02  12:20:00.000    10:00

golang 计算两个时间的时间差

golang 计算两个时间的时间差

package main

import (
    "fmt"
    "time"
)

func main() {
    //Add方法和Sub方法是相反的,获取t0和t1的时间距离d是使用Sub,将t0加d获取t1就是使用Add方法
    k := time.Now()

    //一天之前
    d,_ := time.ParseDuration("-24h")
    fmt.Println(k.Add(d))

    //一周之前
    fmt.Println(k.Add(d * 7))

    //一月之前
    fmt.Println(k.Add(d * 30))

}

go语言计算两个时间的时间差方法

go语言计算两个时间的时间差方法

本文实例讲述了go语言计算两个时间的时间差方法。分享给大家供大家参考。具体分析如下:

go语言计算两个时间的时间差,代码很简单,返回1天前、1周前还是1月前的时间

  1. package mainimport ( "fmt" "time")func main() {//Add方法和Sub方法是相反的,获取t0和t1的时间距离d是使用Sub//将t0加d获取t1就是使用Add方法 k := time.Now() //一天之前 d, _ := time.ParseDuration("-24h") fmt.Println(k.Add(d)) //一周之前 fmt.Println(k.Add(d * 7)) //一月之前 fmt.Println(k.Add(d * 30))}

希望本文所述对大家的Python程序设计有所帮助。

Java中两个日期之间的时间差

Java中两个日期之间的时间差

我必须找到java中两个不同日期对象之间的时间差异,如果该时间超过5秒,我必须使会话无效。

这是场景:

我有一个jsp页面,它每5秒设置一次会话

session.setAttribute( "sessionAccessedAt",new Date() );

我还有另一个jsp页面,每1秒访问一次,

Date date2 = new Date();

现在,我必须在我提到的另一个jsp中进行比较,并使会话无效,

Date date1 = (Date)session.getAttribute("sessionAccessedAt");
Date date2 = new Date();

Differnce = date2 - date1;

因此,如果差异超过5秒,则会话无效。

mysql – 如何在Sql中两个现有行之间的表中插入行

mysql – 如何在Sql中两个现有行之间的表中插入行

我有一个包含9条记录的表,但我想在第5和第6条记录之间插入一行.

最佳答案
如果你坚持的话

UPDATE mytable SET id = id + 1 where id > 5 ORDER BY id ASC

insert into mytable (id,..) values (6,...) 

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