在这篇文章中，我们将为您详细介绍SpringMVCController正在工作但未创建指定的响应URL，它是从请求映射字符串创建URL的内容。此外，我们还会涉及一些关于ajax请求springmvcc

在这篇文章中，我们将为您详细介绍Spring MVC Controller正在工作但未创建指定的响应URL，它是从请求映射字符串创建URL的内容。此外，我们还会涉及一些关于ajax请求spring mvc controller,返回中文字符串显示乱码、asp.net-mvc – ASP.NET MVC,MVCContrib,Structuremap,让它作为controllerfactory工作？、asp.net-mvc – ASP.NET MVC：Mock controller.Url.Action、asp.net-mvc – T4MVC @ Url.Action(MVC.Controller.Action())渲染“？Area =”QueryString中的参数的知识，以帮助您更全面地了解这个主题。

• Spring MVC Controller正在工作但未创建指定的响应URL，它是从请求映射字符串创建URL
• ajax请求spring mvc controller,返回中文字符串显示乱码
• asp.net-mvc – ASP.NET MVC,MVCContrib,Structuremap,让它作为controllerfactory工作？
• asp.net-mvc – ASP.NET MVC：Mock controller.Url.Action
• asp.net-mvc – T4MVC @ Url.Action(MVC.Controller.Action())渲染“？Area =”QueryString中的参数

Spring MVC Controller正在工作但未创建指定的响应URL，它是从请求映射字符串创建URL

我正在研究基于Spring MVC的Web应用程序。所以我在spring mvc中创建了一个项目，并且选择了eclipse IDE.Apache
tomcat 8服务器和jre1.8的spring软件包的版本是4.2.5。在我的项目中，我创建了登录名，登录后工作正常，我将页面重定向到另一个名为“
branchinsert.jsp”的jsp，该jsp放置在另一个文件夹中（login.jsp和branchinsert.jsp来自不同的文件夹）。在Branchinsert.jsp中，Spring
MVC Controller正在运行，但未创建指定的响应URL，它是从请求映射字符串创建url，这意味着如果我给出的模式类似于下面所述，

@RequestMapping(value="/branchsubmitinsert.travel", method=RequestMethod.POST)public ModelAndView submitBranchInsert(@ModelAttribute BranchModel branchModel){    ModelAndView modelAndView = new ModelAndView("/branch/branchinsert");    return modelAndView;}

显示网址404错误/ProjectName/modules/branch/branchsubmitinsert.jsp

实际上，我期望的网址是/branch/branchinsert.jsp（通常会发生这种情况），但是在这里创建了/branch/branchsubmitinsert.jsp网址。为什么？？？？

这是我的代码

web.xml

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"   xmlns="http://java.sun.com/xml/ns/javaee"   xsi:schemaLocation="http://java.sun.com/xml/ns/javaee  http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID"  version="3.0"><display-name>CalicutTravels</display-name>   <servlet>     <servlet-name>spring-dispatcher</servlet-name>       <servlet-class>org.springframework.web.servlet.DispatcherServlet      </servlet-class>  </servlet><servlet-mapping>  <servlet-name>spring-dispatcher</servlet-name>   <url-pattern>/</url-pattern></servlet-mapping><listener><listener-class>    org.springframework.web.context.ContextLoaderListener</listener-class>

ApplicationContext.xml

<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans"       xmlns:context = "http://www.springframework.org/schema/context"       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"       xmlns:mvc="http://www.springframework.org/schema/mvc"       xmlns:p="http://www.springframework.org/schema/p"       xmlns:aop="http://www.springframework.org/schema/aop"       xsi:schemaLocation="http://www.springframework.org/schema/beans        http://www.springframework.org/schema/beans/spring-beans-2.5.xsd       http://www.springframework.org/schema/context        http://www.springframework.org/schema/context/spring-context.xsd       http://www.springframework.org/schema/mvc       http://www.springframework.org/schema/mvc/spring-mvc.xsd">      <context:component-scan base-package="com.classes.controller">          <context:exclude-filter type="annotation"                  expression="org.springframework.stereotype.Controller"/>      </context:component-scan>  </beans>

spring-dispatcher-servlet.xml

 <?xml version="1.0" encoding="UTF-8"?>    <beans xmlns="http://www.springframework.org/schema/beans"       xmlns:context = "http://www.springframework.org/schema/context"       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"       xmlns:mvc="http://www.springframework.org/schema/mvc"       xmlns:p="http://www.springframework.org/schema/p"       xmlns:aop="http://www.springframework.org/schema/aop"       xsi:schemaLocation="http://www.springframework.org/schema/beans        http://www.springframework.org/schema/beans/spring-beans-2.5.xsd       http://www.springframework.org/schema/context        http://www.springframework.org/schema/context/spring-context.xsd       http://www.springframework.org/schema/mvc       http://www.springframework.org/schema/mvc/spring-mvc.xsd">  <context:annotation-config />  <context:component-scan base-package="com.classes.controller">  </context:component-scan>  <mvc:annotation-driven/>   <mvc:resources mapping="/resources/**" location="/resources/" />   <bean id="viewResolver">        <property name="prefix">            <value>/modules/</value>        </property>        <property name="suffix">            <value>.jsp</value>        </property>    </bean>    <!-- declare beans -->      <bean id="userDaoImplementation"/>      <bean id="userServiceImplementation"/>   <!-- declare datasource bean "jdbc:postgresql://hostname:port   /dbname","username", "password");-->  <bean id="dataSource">   <property name="driverClassName" value="org.postgresql.Driver" />   <property name="url" value="jdbc:postgresql://localhost:5432   /db_enterpricer_travel" />   <property name="username" value="vishnu" />   <property name="password" value="root" />  </bean>  </beans>

branchinsert.jsp的表单字段

 <form action=''branchsubmitinsert.travel'' id=''brach_submit'' method=''post'' >            <fieldset>                <legend>  INSERT </legend>                    <table>                        <tr>                            <th> Branch Name :</th>                            <td> <input type="text" name=''branchName'' id=''branchName'' /></td>                        </tr>                        <tr>                          <td colspan="2" align="right"><input type="button"value=''INSERT'' onclick=''return validateBranchInsert()''/></td>                        </tr>                    </table>             </fieldset>        </form>

控制器类BranchController.java

 package com.classes.controller.branch; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.ModelAttribute; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.bind.annotation.RequestMethod; import org.springframework.web.portlet.ModelAndView; import com.classes.service.branch.BranchModel; /** * @author vishnu * */ @Controller @RequestMapping("/branch") public class BranchController { @RequestMapping(value="/branchinsert.travel", method=RequestMethod.GET) public ModelAndView getBranchInsert(){    ModelAndView modelAndView = new ModelAndView("/branch/branchinsert");    return modelAndView; } @RequestMapping(value="/branchupdate.travel", method=RequestMethod.GET) public ModelAndView getBranchUpdate(){    ModelAndView modelAndView = new ModelAndView("/branch/branchupdate");    return modelAndView; } @RequestMapping(value="/branchshow.travel", method=RequestMethod.GET) public ModelAndView getBranchShow(){    ModelAndView modelAndView = new ModelAndView("/branch/branchshow");    return modelAndView; } @RequestMapping(value="/branchdelete.travel", method=RequestMethod.GET) public ModelAndView getBranchDelete(){    ModelAndView modelAndView = new ModelAndView("/branch/branchdelete");    return modelAndView; }@RequestMapping(value="/branchsubmitinsert.travel",method=RequestMethod.POST)public ModelAndView submitBranchInsert(@ModelAttribute BranchModel branchModel){    ModelAndView modelAndView = new ModelAndView("/branch/branchinsert");    modelAndView.addObject("branch",branchModel);    return modelAndView;}}

答案1

我将方法SubmitBranchInsert的返回类型更改为String，如下所示

 @RequestMapping(value="/branchsubmitinsert.travel", method=RequestMethod.POST)public String submitBranchInsert(ModelMap model,@ModelAttribute BranchModel branchModel){    //ModelAndView modelAndView = new ModelAndView("/branch/branchinsert");    //modelAndView.addObject("branch",branchModel);    //return modelAndView;    model.addAttribute("branch", branchModel);    return "/branch/branchinsert";}

现在可以了，但是为什么我不能在这里使用ModelAndView代替String中的Model，这可能是我对Spring
MVC专家们的愚蠢的声音。我只想知道什么时候应该在字符串中使用ModelAndView而不是Model？我不想单独问这个问题，这就是为什么我要用我的答案本身来问这个问题。有人可以帮助我吗？

ajax请求spring mvc controller,返回中文字符串显示乱码

controller:

@RequestMapping("/checkName")

@ResponseBody

public String checkName(String puName){

.............

return "该用户名不存在";

}

ajax:

$.ajax({

type:'post',

url:'checkName',

data:{"puName":$("#puName").val()},

dataType:'text',---------------------------->必须改为json才不显示乱码

success:function(result){

alert(result);

}

}

)'

asp.net-mvc – ASP.NET MVC,MVCContrib,Structuremap,让它作为controllerfactory工作？

public class NewsController : Controller
{
    private readonly INewsService newsService;

    public NewsController(INewsService newsService)
    {
        this.newsService = newsService;
    }

    public ActionResult List()
    {
        var newsArticles = newsService.GetNews();
        return View(newsArticles);
    }
}

public class Application : HttpApplication
{
    protected void Application_Start()
    {
        RegisterIoC();
        RegisterViewEngine(ViewEngines.Engines);
        RegisterRoutes(RouteTable.Routes);
    }

    public static void RegisterIoC()
    {
        ObjectFactory.Initialize(config => {
            config.UseDefaultStructureMapConfigFile = false;
            config.AddRegistry<PersistenceRegistry>();
            config.AddRegistry<DomainRegistry>();
            config.AddRegistry<ControllerRegistry>();
        });
        DependencyResolver.InitializeWith(new StructureMapDependencyResolver());
        ControllerBuilder.Current.SetControllerFactory(typeof(IoCControllerFactory));            
    }
}

protected void Application_Start()
{
    RegisterRoutes(RouteTable.Routes);
    ObjectFactory.Initialize(x =>
    {
        x.AddRegistry(new RepositoryRegistry());
    });
    ControllerBuilder.Current.SetControllerFactory(typeof(StructureMapControllerFactory));
}

public class RepositoryRegistry : Registry
{

    public RepositoryRegistry()
    {
        Scan(x =>
        {
            x.Assembly("MyAssemblyName");
            x.With<DefaultConventionScanner>();
        });

    }

}

ForRequestedType<ISomethingOrOther>().TheDefaultIsConcreteType<SomethingOrOther>();

asp.net-mvc – ASP.NET MVC：Mock controller.Url.Action

controller.Url.Action(action,controller)

var controller = new TestControllerBuilder().CreateController<OrdersController>();

var routes = new RouteCollection();
MvcApplication.RegisterRoutes(routes);
HomeController controller = CreateController<HomeController>();

controller.HttpContext.Response
    .Stub(x => x.ApplyAppPathModifier("/Home/About"))
    .Return("/Home/About");

controller.Url = new UrlHelper(
    new RequestContext(
        controller.HttpContext,new RouteData()
    ),routes
);
var url = controller.Url.Action("About","Home");
Assert.IsFalse(string.IsNullOrEmpty(url));

asp.net-mvc – T4MVC @ Url.Action(MVC.Controller.Action())渲染“？Area =”QueryString中的参数

@Html.Action(MVC.Menu.Index())

<ul id="navHolder">
<li>
    <ul>
        <li><b>@Html.ActionLink("Welcome",MVC.Home.Index())</b>
           ...

<ul id="navHolder">
    <li>
        <ul>
            <li><b><a href="/home/index?Area=">Welcome</a></b>
               ...

@Html.ActionLink("Welcome","Index","Home",new { Area = "" },null)

<# if (MvcVersion >= 2) { #>result.RouteValueDictionary.Add("Area",area ?? "");<# } #>

我们今天的关于Spring MVC Controller正在工作但未创建指定的响应URL，它是从请求映射字符串创建URL的分享已经告一段落，感谢您的关注，如果您想了解更多关于ajax请求spring mvc controller,返回中文字符串显示乱码、asp.net-mvc – ASP.NET MVC,MVCContrib,Structuremap,让它作为controllerfactory工作？、asp.net-mvc – ASP.NET MVC：Mock controller.Url.Action、asp.net-mvc – T4MVC @ Url.Action(MVC.Controller.Action())渲染“？Area =”QueryString中的参数的相关信息，请在本站查询。